cos theta cos2 theta cos3 theta=1/4

If theta=(pi)/(7), prove that cos theta cos2 theta cos3 theta=(1)/(2^(3))

Solve : cos theta cos 2 theta cos 3 theta =(1)/(4) (0 le theta le pi)

If cos theta cos 2 theta cos 3theta = 1//4 for 0 lt theta lt pi then theta =

Solve cos theta cos 2 theta cos 3theta =(1)/(4)

If theta=(pi)/(9), prove that cos theta cos2 theta cos3 theta cos4 theta=(1)/(16)

4cos6 theta cos4 theta cos2 theta=

Prove that, If " "15 theta = pi, "show that," cos theta cos2 theta cos3theta cos 4theta cos5 theta cos6theta cos7theta =1/2^(7)

If 13 theta =pi , " prove that " cos theta cos 2theta cos3 theta cos4theta cos5 theta cos6 theta =1/2^(6)

Solve cos theta * cos 2 theta * cos 3 theta = (1)/( 4), 0 le theta le pi