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Let g(x)=1=x-[x] and f(x)={-1, x < 0 ...

Let `g(x)=1=x-[x] and f(x)={-1, x < 0 , 0, x=0 and 1, x > 0,` then for all `x, f(g(x))` is equal to (i) x (ii) 1 (iii) f(x) (iv) g(x)

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