" 26."x^(2)-2ax+(a^(2)-b^(2))=0

36x^(2)-12ax+(a^(2)-b^(2))=0

x^(2)-2ax-(4b^(2)-a^(2))=0

Solve 4x^(2)-4ax+(a^(2)-b^(2))=0.

The roots of the equation x^(2)+2ax+a^(2)+b^(2)=0 are

The roots of the equation x^(2)+2ax+a^(2)+b^(2)=0 are

The locus of the midpoints of the chords of the circle x^(2)+y^(2)-ax-by=0 which subtend a right angle at ((a)/(2),(b)/(2)) is ax+by=0ax+by=a^(2)=b^(2)x^(2)+y^(2)-ax-by+(a^(2)+b^(2))/(8)=0x^(2)+y^(2)-ax-by-(a^(2)+b^(2))/(8)=0

The polar of the line ax+by+3a^(2)+3b^(2)=0 w.r.t. to the circle x^(2)+y^(2)+2ax+2by-a^(2)-b^(2)=0 is

If a circle passes through the point (a, b) and cuts the circle x^2 + y^2 = 4 orthogonally, then the locus of its centre is (a) 2ax+2by-(a^(2)+b^(2)+4)=0 (b) 2ax+2by-(a^(2)-b^(2)+k^(2))=0 (c) x^(2)+y^(2)-3ax-4by+(a^(2)+b^(2)-k^(2))=0 (d) x^(2)+y^(2)-2ax-3by+(a^(2)-b^(2)-k^(2))=0

int (ax^(2)-b)(dx)/(x sqrt(c^(2))x^(2) -(ax^(2) + b^(2))^(2)