sin x+sin2x+sin3x=0" if "

Find number of solution of equation sin x-sin2x+sin3x=0 in 0<=x<=(pi)/(2) (a) 2( b) 3(c)4 (d) 5

If 0<=x<(pi)/(2), then the number of values of x for which sin x-sin2x+sin3x=0, is

If 0lexltpi/2, then the number of values of x for which sinx-sin2x+sin3x=0 is

Find the number of solutions of the equation 1+cos x+cos2x+sin x+sin2x+sin3x=0,x in[0,pi]

The number of solutions of the equation 1+cos x+cos2x+sin x+sin2x+sin3x=0 which satisfy the condition (pi)/(2)<|3x-(pi)/(2)|<=pi is

int_(0)^(pi//2)sinx sin2x sin3x sin 4x dx=

int_(0)^(pi//2)sinx sin2x sin3x sin 4x dx=

int_(0)^(pi//2)sinx sin2x sin3x sin 4x dx=

(sin x) / (sin2x sin3x) + (sin x) / (sin3x sin4x) + (sin x) / (sin4x sin5x) + .... n