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[" Q10: "sin A+sin3A+sin5A+sin7A=],[bigc...

[" Q10: "sin A+sin3A+sin5A+sin7A=],[bigcirc" A "4sin A cos2A cos4A],[bigcirc" B "quad " 4sinAcos2Acos3A "],[" C "4" cosAsin2Asin4"A],[" D "4" cosAcos2Asin4"A]

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(sin A+sin3A+sin5A+sin7A)/(cos A+cos3A+cos5A+cos7A)=tan4A

( sin 4 A sin 3A - sin 5A sin 2A+ sin 7A sin 4A )/(cos 2A cos 3A - cos 2A * cos 7A + cos A * cos 10A )=

sin2A+2sin4A+sin6A=4cos^2Asin4A

Prove that: sinA+sin2A+sin4A+sin5A= 4sin3A. cosA/2.cos(3A)/(2)

(sin A sin2A + sin3A sin6A + sin4A sin13A) / (sin A cos2A + sin3A cos6A + sin4A cos13A) = tan9A

sin4A=4sinAcos^3A-4cosAsin^3A

Prove that: (sin2A sin3A-sin4A sin5A+sin3A sin6A)/(cos2A cos3A-cos4A cos5A+cos3A cos6A)=tan A tan4A

sin4A=4cos^(3)A sin A-4sin^(3)A cos A

sin 2A + sin 2B + sin 2 (A-B)= A) 4 sin A * sin B * sin (A-B) B) 4 sin A * cos B * cos (A-B) C) 4 cos A * sin B * cos (A-B) D) 4 cos A * cos B * sin (A-B)