" Let "S_(n)=^(n)C_(0)^(n)C_(1)+^(n)C_(1)^(n)C_(2)+......+^(n)C_(n-1)^(n)C_(n)." If "(S_(n+1))/(S_(n))=(15)/(4)" find the sum of squares of all possible values "o

Let S_(n)=""^(n)C_(0)""^(n)C_(1)+""^(n)C_(1)""^(n)C_(2)+…..+""^(n)C_(n-1)""^(n)C_(n). "If" (S_(n+1))/(S_(n))=(15)/(4) , find the sum of all possible values of n (n in N)

The value of .^(n)C_(0).^(n)C_(n)+.^(n)C_(1).^(n)C_(n-1)+...+.^(n)C_(n).^(n)C_(0) is

if S_(n)=C_(0)C_(1)+C_(1)C_(2)+...+C_(n-1)C_(n) and (S_(n+1))/(S_(n))=(15)/(4) then n is

C_(0)^(n)C_(n)^(n+1)+C_(1)^(n)C_(n-1)^(n)+C_(2)^(n)*C_(n-2)^(n-1)+.........+C_(n)^(n)*C_(0)^(1)=2^(n-1)(n+2)

Evaluate .^(n)C_(0).^(n)C_(2)+.^(n)C_(1).^(n)C_(3)+.^(n)C_(2).^(n)C_(4)+"...."+.^(n)C_(n-2).^(n)C_(n) .

If S_n=^nC_0.^nC_1+^nC_1.^nC_2+.....+^nC_(n-1).^nC_n and if S_(n+1)/S_n=15/4 , then the sum of all possible values of n is (A) 2 (B) 4 (C) 6 (D) 8

Find the sum 1.^(n)C_(0) + 3 .^(n)C_(1) + 5.^(n)C_(2) + "….." + (2n+1).^(n)C_(n) .

sum_(n=1)^(oo) (""^(n)C_(0) + ""^(n)C_(1) + .......""^(n)C_(n))/(n!) is equal to

sum_(n=1)^(oo) (""^(n)C_(0) + ""^(n)C_(1) + .......""^(n)C_(n))/(n!) is equal to