Home
Class 12
PHYSICS
A smooth wire frasme is in the shape of ...

A smooth wire frasme is in the shape of a parabola `y = 5x^(2)` . It is being rotated about y-axis with an angular velocity `omega`. A small bead of mass `(m = 1 kg)` is at point `P` and is in equilibrium with respect to the frame. Then the angular velocity `omega` is `(g = 10 m//s^(2))`

Promotional Banner

Similar Questions

Explore conceptually related problems

A ring of mass m and radius R is being rotated about its axis with angular velocity omega . If a increases then tension in ring

A ring of mass m and radius R is being rotated about its axis with constant angular velocity omega in the gravity free space. Find tension in the ring.

A ring of mass m and radius R is given a charge q. It is then rotated about its axis with angular velocity omega .Find (iii)Magnetic moment of ring.

A ring of mass m and radius R is given a charge q. It is then rotated about its axis with angular velocity omega .Find (iii)Magnetic moment of ring.

A thin circular ring of mass M and radius R is rotating about its axis with constant angular velocity omega . The objects each of mass m are attached gently to the ring. The wheel now rotates with an angular velocity.

A thin circular ring of mass M and radius R is rotating about its axis with constant angular velocity omega . The objects each of mass m are attached gently to the ring. The wheel now rotates with an angular velocity.

A thin circular ring of mass m and radius R is rotating about its axis with a constant angular velocity omega . Two objects each of mass M are attached gently to the opposite ends of a diameter of the ring. The ring now rotates with an angular velocity omega' =

A thin circular ring of mass M and radius r is rotating about its axis with a constant angular velocity omega , Two objects, each of mass m, are attached gently to the opposite ends of a diameter of the ring. The wheel now rotates with an angular velocity omega=