A circle s passes through the point ( 0,1) and is orthogonal to the circles ` ( x - 1)^(2) + y^(2) = 16` and ` x^(2) + y^(2) = 1 `. Then

Find the centre of the circle that passes through the point (1,0) and cutting the circles x^(2) + y ^(2) -2x + 4y + 1=0 and x ^(2) + y ^(2) + 6x -2y + 1=0 orthogonally is

Find the centre of the circle that passes through the point (1,0) and cutting the circles x^(2) + y ^(2) -2x + 4y + 1=0 and x ^(2) + y ^(2) + 6x -2y + 1=0 orthogonally is

Find the equation of the circle which passes through (1, 1) and cuts orthogonally each of the circles x^2 + y^2 - 8x - 2y + 16 = 0 and x^2 + y^2 - 4x -4y -1 = 0

A circle passes through the points (0,0) and (0,1 ) and also touches the circie x^(2)+y^(2)=16 The radius of the circle is

The centre of a circle passing through the points (0,0),(1,0) and touching the circle x^(2)+y^(2)=9 is

The equation of the circle which pass through the origin and cuts orthogonally each of the circles x^(2)+y^(2)-6x+8=0 and x^(2)+y^(2)-2x-2y-7=0 is

If a circle Passes through point (1,2) and orthogonally cuts the circle x^(2)+y^(2)=4, Then the locus of the center is:

Find the question of the circle which passes through (1, 1) and cuts orthogonally each of the circles. x^2 + y^2 - 8x - 2y + 16 = 0and "___"(1) x^2 + y^2 - 4x - 1 = 0. "___"(2)