100 ml of 0.1 M `NaAl(OH)_(2)CO_3` is neutralised by 0.25 N HCl to form `NaCl, AlCl_3` and `CO_2`.Volume of HCl required is

25 mL, 0.2 M Ca(OH)_2 is neutralised by 10 mL of 1 M HCl. then pH of resulting solution is-

When 100 " mL of " 0.1 M Ba(OH)_(2) is neutralised with a mixture of x " mL of " 0.1 M HCl and y " mL of " 0.2 M H_(2)SO_(3) using methyl orange indicator what is value of x and y?

When 100 " mL of " 0.1 M Ba(OH)_(2) is neutralised with a mixture of x " mL of " 0.1 M HCl and y " mL of " 0.2 M H_(2)SO_(3) using methyl orange indicator what is value of x and y?

The volume of 0.25 MH_(3)PO_(3) required to neutralise 25 ml of 0.03 M Ca(OH)_(2) is

When 100 mL of 0.1 M NaCN solution is titrated with 0.1 M HCl solution the variation of pH of solution with volume of HCl added will be :

When 100 mL of 0.1 M NaCN solution is titrated with 0.1 M HCl solution the variation of pH of solution with volume of HCl added will be :

When 100 mL of 0.1 M NaCN solution is titrated with 0.1 M HCl solution the variation of pH of solution with volume of HCl added will be :