the graph of the conic `x^2-(y-1)^2=1` has one tangent line with positive slope that passes through the origin . The point of the tangency being `(a,b)` then find the value of `sin^-1(a/b)`

The graph of the conic x^(2)-(y-1)^(2)=1 has one tangent line with positive slope that passes through the origin. The point of tangency being (a, b). Q. Length of the latusrectum of the conic is

The graph of the conic x^(2)-(y-1)^(2)=1 has one tangent line with positive slope that passes through the origin. The point of tangency being (a, b). Length of the latusrectum of the conic is (a) 1 (b) sqrt(2) (c) 2 (d) 4

The graph of the conic x^(2)-(y-1)^(2)=1 has one tangent line with positive slope that passes through the origin. The point of tangency being (a, b). Length of the latusrectum of the conic is (a) 1 (b) sqrt(2) (c) 2 (d) 4

The graph of the conic x^(2)-(y-1)^(2)=1 has one tangent line with positive slope that passes through the origin. The point of tangency being (a, b). Q. If e be the eccentricity of the conic, then the value of (1+e^(2)+e^(4)) is

The graph of the conic x^(2)-(y-1)^(2)=1 has one tangent line with positive slope that passes through the origin. The point of tangency being (a, b). Q. If e be the eccentricity of the conic, then the value of (1+e^(2)+e^(4)) is

The graph of the conic x^(2)-(y-1)^(2)=1 has one tangent line with positive slope that passes through the origin. The point of tangency being (a, b). Q. If e be the eccentricity of the conic, then the value of (1+e^(2)+e^(4)) is

Determine the equation of the passing through the origin, the slope of the tangent of which at any point (x,y) is (x+1)/(y+1) .

Find the equation of the cure which passes through the origin and has the slope x+3y-1 at the point (x,y) on it.