Using Mathematical induction. For all `n in N`. Show that
`a+(a+d)+(a+2d)+…………..n "upto n terms" = n/2 [2a+(n-1)d]`.

Prove the following by using the principle of mathematical induction for all n in N a + (a+d)+(a+2d) +……+ (a+(n-1)d) = n/2 [2a + (n-1)d]

By the Principle of Mathematical Induction, prove the following for all n in N : a+ (a+d)+(a+2d)+....+ [a+(n-1)d] =n/2 [2a + (n-1)d] .

For all ninNN , prove by principle of mathematical induction that, a+(a+d)+(a+2d)+ . . . to n terms =(n)/(2)[2a+(n-1)d] .

Using the principle of finite Mathematical Induction prove the following: (vi) 2+3.2+4.2^(2)+………."upto n terms" = n.2^(n) .

Prove that a+(a+d)+(a+2d)+........n "terms"=n/2(2a+(n-1)d)

Using mathematical induction prove that (2n+7) lt (n+3)^2 for all n in N

Using Mathematical Induction, prove that statement for all n in N 1.2.3+2,3,4+……….+("upto n terms")=(n(n+1)(n+2)(n+3))/(4) .

Using mathematical induction prove that : d/(dx)(x^n)=n x^(n-1) for all n in NN .

Prove the following by using the principle of mathematical induction for all n in N 1^2 +3 ^2 + 5^2 +………..+ (2n-1)^2 = (n(2n - 1)(2n+1))/(3)