दर्शाइये कि फलन `f : R to R` , f (x ) = ax + b जहाँ a , b `in R , a ne 0 ` एकैकी आच्छादक फलन हैं ।

If f:R to R where f(x)= ax +cosx , if f is bijective, then

Let f : R to R be defined by f(x) = ax + b AA x in R Where a,b in R and a ne 1 If (fofofofof)(x) = 32x + 93 , then value of b is ………….

Evalute : int e^(ax) sin (bx+c) dx , (a, b, c in R, b ne 0) on R.

Let f: R to R be defined by f(x) =x/(x+1), x ne -1 If a,b in R and ab ne 0, f (a/b) + f(b/a) and a+b ne 0 is equal to

Suppose, f,g: R to R be defined by f(x) = ax + b, g(x) =cx + d , where a,b,c,d in R and ac ne 0 , if f(g(x)) = g(f(x)) AA x in R , then

Let f(x) = ax^(2) - bx + c^(2), b ne 0 and f(x) ne 0 for all x in R . Then

Let f(x) = ax^(2) - bx + c^(2), b ne 0 and f(x) ne 0 for all x in R . Then

Let f(x) = ax^(2) - bx + c^(2), b ne 0 and f(x) ne 0 for all x in R . Then

Let f : R to R : f (x) =x^(2) " and " g: R to R : g (x) = (x+1) Show that (g o f) ne (f o g)