हल कीजिए :
`x+y=3.3`
`(0.6)/(3x-2y)=-1`

Solve using the method of elimination by equating coefficients : x + y = 3.3 and ( -0.6 )/(3x - 2y) = 1.

3x+2y=1, 6x+4y=

Find the point of intersection of the straight lines : (i) 2x+3y-6=0 , 3x-2y-6=0 (ii) x=0 , 2x-y+3=0 (iii) (x)/(3)-(y)/(4)=0 , (x)/(2)+(y)/(3)=1

Solve for x and y 2/(3x+2y)+3/(3x-2y)=17/5,5/(3x+2y)+1/(3x+2y)=6/5

( 1 ) /( 2x ) + (1 ) /( 3y ) = 2, (1) /( 3x ) + (1) /( 2y ) = ( 13) /( 6) ( x ne 0 , y ne 0 )

Solve: {:(x - 2y = 6),(3x + 6y = 0):}

If (2x + y + 2)/(5) = ( 3x - y + 1)/( 3 ) = ( 2 x + 2y + 1 )/(6) then

Solve for x and y: 2x + 3y + 1 = 0, 3x + 2y - 11 = 0