बुलियन बीजगणितीय में सिद्ध किजिए की ` bar(A+B)=bar(A).bar(B)`

Compute bar(a) xx (bar(b) + bar(c )) + bar(b) xx (bar(c ) +bar(a)) + bar(c ) xx (bar(a)+bar(b))

The non-zero vectors bar(a) , bar(b) , bar(c ) holds | (bar(a) .bar(b) ).bar( c) |=| bar(a) ||bar(b)|| bar( c) if

If bar(a) = 2bar(i) - 3bar(j) + bar(k) and bar(b) = bar(i) + 4bar(j) -2bar(k) , then find (bar(a) + bar(b))xx(bar(a)-bar(b))

If bar(a),bar(b) and bar( c ) are unit vectors such that bar(a)+bar(b)+bar( c )=bar(0) , then the value of bar(a).bar(b)+bar(b).bar( c )+bar( c ).bar(a)=…………

If bar(a) is perpendicular to bar(b) then bar(a)*bar(b) is

For vectors bar(a),bar(b),bar( c ),|bar(a)-bar( c )|=|bar(b)-bar( c )| then the value (bar(b)-bar(a)).(bar( c )-(bar(a)+bar(b))/(2))= ………..

If bar(a) and bar(b) be non collinear vectors such that |bar(a)times bar(b)|=bar(a).bar(b) then the angle between bar(a) and bar(b) is

bar(a) , bar(b) and bar(c) are three vectors such that bar(a) + bar(b) + bar(c) = bar(0) and |bar(a)| =2, |bar(b)| =3, |bar(c)| =5 ,then bar(a) . bar(b) + bar(b) . bar(c) + bar(c) . bar(a) equals