Extremities of the latera recta of the ellipses `(x^2)/(a^2)+(y^2)/(b^2)=1(a > b)` having a given major axis 2a lies on

Extrremities of the latera recta of the ellipses (x^(2))/(a^(2))+(y^(2))/(b^(2))=1(a>b) having a given major axis 2a lies on

Extremities of the latus rectum of the ellipses (x^(2))/(a^(2))+(y^(2))/(b^(2)) =1 (a gt b) having a major axis 2a lies on a. x^(2)=a(a-y) b. x=a(a+y) c. y^(2)=a(a+x) d. y^(2)=a(a-x)

Ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1(a>b) Equation of the circle described on major axis as diameter is

End points of the major axis of the ellipse ((x-h)^(2))/(a^(2))+((y-k)^(2))/(b^(2))=1(a

Equation of major axis of the ellipse ((x-h)^(2))/(a^(2))+((y-k)^(2))/(b^(2))=1 (a

If the circle whose diameter is the major axis of the ellipse (x^(2))/(a^(2))+(y^(2))/(b^(2))=1(a gt b gt 0) meets the minor axis at point P and the orthocentre of DeltaPF_(1)F_(2) lies on the ellipse, where F_(1) and F_(2) are foci of the ellipse, then the square of the eccentricity of the ellipse is

Find the eccentric angles of the extremities of the latus recta of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1

Find the eccentric angles of the extremities of the latus recta of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1

Find the eccentric angles of the extremities of the latus recta of the ellipse (x^2)/(a^2)+(y^2)/(b^2)=1

Find the equation of the ellipse in the form x^2/a^2+y^2/b^2=1(a>b) , given : major axis is 16, minor axis is 12.