The roots of the equation `|{:(" "1,t-1," "1),(t-1," "1," "1),(" "1," "1,t-1):}|=0` are

Let's find the roots of the equations frac(t+12)(16) - t = 6frac(1)(2) - frac(1)(12)

If y(t) is the solution of the differential equation (t+1)(dy)/(dt)-ty=1 and y(0)=-1 , then the value of y at t=1 is -

The equation x =1/2 (t+ (1)/(t)), y = 1/2 (t - 1/t), t ne 0 represents

The equation x =1/2 (t+ (1)/(t)), y = 1/2 (t - 1/t), t ne 0 represents

The equations x=(1)/(2)(t+(1)/(t)), y=(1)/(2)(t-(1)/(t)), t ne 0 , represent

If the system of homogeneous equations tx+(t+1)y+(t-1)z=0 (t+1)x+ty+(t+2)z=0 (t-1)x+(t+2)y+tz=0 in x,y,z has a non-trivial solution, then t is a root of the equation

IF A=[{:(2,0,1),(-1,1,5):}] ,B=[{:(-1,1,0),(0,1,-2):}] then find (AB^T)^T

(4)/(t-1)=(3)/(w-1) If in the equation above tne1 and wne1 , then t=

If tantheta= t, then tan2theta+sec2theta is equal to (a) (1+t)/(1-t) (b) (1-t)/(1+t) (c) (2t)/(1-t) (d) (2t)/(1+t)