A long narrow horizontal slit lies `1mm`above a plane mirror.The interference pattern produced by the slit and its image is viewed on a screen distant `1m`from the slit .The wavelength of light is`600nm`.Find the distance of first maximum above the mirror.

A long narrow horizontal slit lies 1 mm above a plane mirror. The interference pattern produced by the slit and its and its image is viewed on a screen sum distance 1m from the slit. The wavelength of light is 600 nm . Then the distance of the first maxima above the mirror is equal to (d lt lt D) :

A long narrow horizontal slit lies 1 mm above a plane mirror. The interference pattern produced by the slit and its and its image is viewed on a screen sum distance 1m from the slit. The wavelength of light is 600 nm . Then the distance of the first maxima above the mirror is equal to (d lt lt D) :

A long narrow horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and that after reflection is seen on a screen 1.0 m away from the slit, Find the fringe-width if the light used has a wavelength of 700 nm.

A long narrow horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and that after reflection is seen on a screen 1.0 in away from the slit, Find the fringe-width if the light used has a wavelength of 700 nm.

A long horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and the after reflection is seen on a screen 1 m away from the slit. If the mirror reflects only 64% of the light falling on it, the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen is

A long horizontal slit is placed 1 mm above a horizontal plane mirror. The interference between the light coming directly from the slit and the after reflection is seen on a screen 1 m away from the slit. If the mirror reflects only 64% of the light falling on it, the ratio of the maximum to the minimum intensity in the interference pattern observed on the screen is

In a Lloyds's mirror experiment as narrow slit S transmitting a light of wavelength lambda is placed 3 mm above a small plane mirror ( as shown). The light coming directly from the the slit and that coming after the reflection interfere on a screen placed at a distance of 90 cm from the slit. Length of mirror is 2 mm and the middle point of mirror is 2 mm from point P. If the mirror is shifted towards left then how does the fringe pattern on screen changes ?

A source emitting light of wavelengths 480 nm and 600 nm is used in a double slit interference experiment. The separation between the slits is 0.25 mm and the interference is observed on a screen placed at 150 cm from the slits. Find the linear separation between the first maximum (next to the central maximum) corresponding to the two wavelengths.