A car starts from rest and moves with uniform acceleration for time t then it moves with uniform speed of 60 km/h for time 3t and comes to rest. Find the average speed of car in its total journey.

A car starts from rest and travels with uniform acceleration a, for some time and then with uniform retardation beta and comes to rest. If the total time of car is 't', the maximum velocity attained by it is given by

A car starts from rest and travels with uniform acceleration prop , for same time and then with uniform retardation beta and comes to rest. The time of motion t. Find the maximum velocity attained by it, (alphabetat//(alpha+beta))

A car starts from rest and moves with a uniform acceleration of 1 m//s^2 ? for 10 seconds. It then moves with a uniform velocity for 30 seconds. The brakes are then applied and the car is brought to rest in 10 seconds. Find the total distance covered by the car.

A car starts to move from rest with uniform acceleration 10 ms^(-2 ) then after 5 sec, what is its velocity?

A car starts from rest and moves with uniform acceleration 'a' .At the same point a bike crosses with a uniform velocity 'u'. When and where will they meet ?What is the velocity of car with respect to the bike at the time of meeting?

A car starts from rest and moves with uniform acceleration a on a straight road from time t=0 to t=T . After that, a constant deceleration brings it to rest. In this process the average speed of the car is

A car starts from rest and moves with uniform acceleration a on a straight road from time t=0 to t=T . After that, a constant deceleration brings it to rest. In this process the average speed of the car is