5yquad 18*ab(x^(2)+y^(2))+xy(a^(2)+b^(2))

Fractorise: ab (x ^(2) + y^(2) ) + xy (a^(2) + b ^(2)).

Factorise: ab (x ^(2) + y ^(2)) - xy (a ^(2) + b ^(2))

Find each of the following products: (i) 5a^(2) b^(2) xx (3a^(2) - 4ab + 6b^(2)) (ii) (-3x^(2)y) xx (4x^(2) y - 3xy^(2) + 4x - 5y)

If (x+1)/(x-1)=(a)/(b) and (1-y)/(1+y)=(b)/(a), then the value of (x-y)/(1+xy) is (2ab)/(a^(2)-b^(2)) (b) (a^(2)-b^(2))/(2ab) (c) (a^(2)+b^(2))/(2ab) (d) (a^(2)-b^(2)backslash)/(ab)

If a=(x)/(x+y) and b=(y)/(x-y), then (ab)/(a+b) is equal to (a) (xy)/(x^(2)+y^(2)) (b) (x^(2)+y^(2))/(xy)( c) (x)/(x+y) (d) ((y)/(x+y))^(2)

Add : 4x^(2)y, - 3xy^(2), -5xy^(2), 5x^(2)y

Simplify : (x^(2) - y^(2) + 2xy + 1) - (x^(2) + y^(2) + 4xy - 5)