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If A=[{:(costheta,sintheta),(sintheta,-c...

If `A=[{:(costheta,sintheta),(sintheta,-costheta):}]`, `B=[{:(1,0),(-1,1):}]` , `C=ABA^(T)`, then `A^(T)C^(n)A` equals to `(n in I^(+))`

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(1+sintheta-costheta)/(1+sintheta+costheta)=