Two ballons are simultaneously released from two buildings A and B. Balloon from A rises with constant velocity `10ms^(-1)` While the other one rises with constant velocity of `20ms^(-1)` Due to wind the balloons gather horizontal velocity `V_(x)=0.5` y, where 'y' is the height from the point of release. The buildings are at a distance of `250` m & after some time 't' the balloons collide.

Two balls of equal mass are projected upwards simultaneously, one from the ground with initial velocity 50ms^-1 and the other from a 40m tower with initial velocity of 30ms^-1 . The maximum height attained by their COM will be

Two particles , one with constant velocity 50 m//s and the other with uniform acceleration 10 m//s^(-2) . Start moving simultaneously from the same place in the same direction. They will be at a distance of 125m other after.

A stone is dropped from a balloon rising upwards with a velocity of 16 ms^(-1) . The stone reaches the ground in 4 s. Calculate the height of the balloon when the stone was dropped.

A balloon starts rising from the surface of the earth with vertical component of velocity v_(0) . The balloon gathers a horizontal velocity v_(x) = ay , where a is a constant and y is the height from the surface of the earth, due to a horizontal wind. Determine (a) the equation of trajectory of the balloon. (b) the tangential, normal and total acceleration of the balloon as function of y.

A ball is thrown with a velocity of 30 ms^(-1) from the top of a building 200m high . The ball makes an angle of 30^(@) with the horizontal . Calculate the distance from the foot of the building where the ball strikes the ground (g=10ms^(-2)) .

Two particles are thrown simultaneously from points A and B with velocities u_1 = 2ms^(-1) and u_2 - 14 ms^(-1) , respectively, as shown in figure. The relative velocity of B as seen from A in

A ball is dropped from the top of a building 100 m high. At the same instant another ball is thrown upwards with a velocity of 40ms^(-1) form the bottom of the building. The two balls will meet after.

A balloon starts rising from the earth's surface. The ascension rate is constant and equal to v_(0) . Due to the wind. The balloon gathers the horizontal velocity component v_(x)=ky , where k is a constnat and y is the height of ascent. Find how the following quantities depednd on the height of ascent. (a) the horizontal drift of the balloon x (y) (b) the total tangential and normal accelrations of the balloon.

A balloon starts rising from the surface of the earth with a verticle component of velocity v_(0) . The baloon gathes a horizontal velocity v_(x)=lambda_(y) , where lambda is a constant and y is the height from the surface of earth, due to a horizontaln wind. determine (a) the equation of trajectory and (b) the tangential, normal and total acceleration of the balloon as a function of y .

A body is simultaneously given two velocities, one 10 ms^(-1) due east and other 20 ms^(-1) due north-west. Calculate the resultant velocity.