The empirical formula of a gaseous compound `CH_(2)`. The density of the compound is 1.25 gm/lit at S.T.P. The molecular formula of the compound is 'X'

Define empirical formula of a compound.

The empirical formula of a compound is CH_(2)O . 0.0835 moles of the compound contains 1.0 g of hydrogen Molecular formula of the compound is

0.1653 g aluminium reacts completely with 0.652 g chlorine to form chloride of aluminium. a. What is the empirical formula of the compound? b. If molecular mass of the compound is 267 amu, calculate the molecular formula of the compound.

A gaseous hydrocarbon with empirical formula CH_(2) has a density of 12.5 g gL^(-1) at N.T.P The molecular formula of the compound is

The empirical formula of a compound is CH_(2) . IF one mole of the compound has a mass of 42 g , its molecular formula is

The empirical formula of anorganic compound is CH_2 .The mass of 1 mol of it is 42 gm.The molecular formula of the compound is:

The empirical formula of a compound is CH_(2)O .If the vapour density is 60, what would be the molecular formula of the compound?