The vertical and horizontal displacements of a projectile thrown from a point on the ground at time t are given by `y=6t-5t^(2)` and `x=8t` respectively,where x and y are in meters and t is in seconds.The time of flight of the projectile in seconds is ?

The x and y coordinates of the particle at any time are x=5t-2t^(2) and y=10t respectively, where x and y are in meters and t in seconds. The acceleration of the particle at t=2s is:

The x and y coordinates of the particle at any time are x=5t-2t^(2) and y = 10t respectively, where x andy are in metres and / in seconds. The acceleration of the particle at t = 5 s is

The horizontal and vertical displacements of a projectile at time t are x=36t and y=48t-4.9t^(2) respectively where x ,y are in meters and t in seconds.Initial velocity of the projectile in m/s is

The x and y coordinates of a particle at any time t are given by x = 2t + 4t^2 and y = 5t , where x and y are in metre and t in second. The acceleration of the particle at t = 5 s is

The height y and the distance x along the horizontal plane of a projectile on a certain planet (with no surrounding atmosphere) are given by y = (8t-5t^(2)) meter and x = 6t meter , where t is in second. The velocity with which the projectile is projected is

The height y and the distance x along the horizontal plane of a projectile on a certain planet [with no surrounding atmosphere] are given by y=[5t-8t^2] metre and x = 12t metre where t is the time in second. The velocity with which the projectile is projected is:

y(x, t) = 0.8//[4x + 5t)^(2) + 5] represents a moving pulse, where x and y are in meter and t in second. Then