`int(sin^(6)theta+cos^(6)theta)/(sin^(2)theta cos^(2)theta)d theta=`

sin^(6)theta+cos^(6)theta+3sin^(2)theta cos^(2)theta=1

int(2sin theta cos theta)/(sin^(4)theta+cos^(4)theta)d theta

The value of the expression sin^(6)theta+cos^(6)theta+3sin^(2)theta*cos^(2)theta equals

What is ( sin ^(6) theta - cos ^(6) theta )/( sin ^(2) theta - cos ^(2) theta) equal to ?

The value of sin^(8)theta+cos^(8)theta+sin^(6)theta cos^(2)theta+3sin^(4)theta cos^(2)theta+cos^(6)theta sin^(2)theta+3sin^(2)thetacos^(4)theta is equal to

4(sin^(6)theta+cos^(6)theta)-6(sin^(4)theta+cos^(4)theta) is equal to

The value of 8(sin^(6)theta+cos^(6)theta)-12(sin^(4)theta+cos^(4)theta) is equal to

Prove that: sin^(6) theta + cos^(6) theta =1 - 3 sin^(2) theta cos^(2) theta

Prove that sin^(6)theta+cos^(6)theta=1-3sin^(2)theta cos^(2)theta