An electron of mass `m` and charge `e` initially at rest gets accelerated by a constant electric field `E`. The rate of change of de-Broglie wavelength of this electron at time `t` ignoring relativistic effects is

An electron (-|e|, m) is released in Electric field E from rest. rate of change of de-Broglie wavelength with time will be.

An electron of mass m_e and a proton of mass m_p are accelerated through the same potential difference. The ratio of the de Broglie wavelength associated with an electron to that associated with proton is

An electron of mass m and charge q is accelerated from rest in a uniform electric field of strength E. The velocity acquired by it as it travels a distance l is

An electron of mass m and charge e is accelerated from rest through a potential difference V in vacuum. The final speed of the electron will be

The de Broglie wavelength of an electron accelerated by an electric field of V volt is given by:

An electron of charge e and mass m is accelerated from rest by a potential difference V . the de Broglie wavelength is

An electron (mass m) with initial velocity vecv = v_0 hati + 2v_0 hatj is in an electric field vecE = E_0 hatk . If lamda_0 is initial de-Broglie wavelength of electron, its de-Broglie wave length at time t is given by :

An electron is accelerated through a potential difference of V volit .Find th e de Broglie wavelength associated with electron.