Electron in hydrogen atom first jumps from third excited state to second excited state and then form second excited state to first excited state. The ratio of wavelength `lambda_(1): lambda_(2)` emitted in two cases is

In a hydrogen atom,electron moves from second excited state to first excited state and then from first excited state to ground state.The ratio of wavelengths is

An electron in hydrogen atom first jumps form second excited state to first excited state and then form first excited state to ground state. Let the ratio of wavelength, momentum and energy of photons emitted in these two cases be a, b and c respectively, Then

The ratio of wavelenghts of photons emitted when hydrogen atom de-excites from third excieted state to second excited state then de-excities form second excited state to first excited state is :

When a hydrogen atom is excited from ground state to first excited state then

When a hydrogen atom is excited from ground state to first excited state, then

The ratio of energies of hydrogen atom in its first excited state to third excited state is

The ratio of the areas of the orbit for the second excited state to the first excited state for the hydrogen atom is