The binding energy of an electron in the ground state of He is equal to 24.6 eV: Find the energy required to remove both electrons.

The binding energy of an electron in the gorund state of He atom is equal to E_0 = 24.6 eV. Find the energy required to remove both electrons form the atom.

The biding energy of an electron in the ground state of He atom is 25 eV. Find the energy required to remove both the electrons.

If the binding energy of the electron in a hydrogen atom is 13.6 eV , the energy required to remove the electron from the first excited state of Li^(++) is

If the bineding energy of the electron of the electron in a hydrogen atom is 13.6 eV the energy required to remove the electron from the first excited state of Li ^(++) is

The minimum energy required to remove an electron is called

" The binding energy for the third electron in the ground state of "Li" -atom (in eV) should be "

The binding energy of e^(-) in ground state of hydrogen atom is 13.6 eV . The energies required to eject out an electron from three lowest states of He^(+) atom will be (in eV):