The position vector of a moving particle at `t` sec is given by `r=3hat i+4t^(2)hat j-t^(3)hat k`. Its displacement during an interval from `1s` to `3s` is

The position vector of a moving particle at 't' sec is given by vec r=3hat i+4t^(2)hat j-t^(3)hat k .Its displacement during an interval of t =1 s to 3 sec is (A) hat j-hat k (B) 3hat i+4hat j-hat k (C) 9hat i+36hat j-27hat k (D) 32hat j-26hat k

The position vector of a moving particle at seconds in given by vecr=3hati+4t^(2)hatj-t^(3)hatk .Its displacement during an interval of 1s to 3s is

The position vector of a particle is determined by the expression vec r = 3t^2 hat i+ 4t^2 hat j + 7 hat k . The displacement traversed in first 10 seconds is :

If the position vector of a particle is given by vec r =(4 cos 2t) hat j + (6t) hat k m , calculate its acceleration at t=pi//4 second .

Position vector of a particle moving in space is given by : vec(r)=3sin t hat i+3 cos t hatj+4 t hatk Distance travelled by the particle in 2s is :

The position of a particle is given by vec(r) = 3that(i) - 4t^(2)hat(j) + 5hat(k). Then the magnitude of the velocity of the particle at t = 2 s is

If the position vector of a particle is given by vec(r ) = (cos 2t) hat(i) + (sin 2 t) hat(j) + 6 t hat(k) m . Calculate magnitude of its acceleration (in m//s^(2) ) at t = (pi)/(4)

The time dependence of the position of a particle of mass m = 2 is given by vec(r) (t) = 2t hat(i) - 3 t^(2) hat(j) Its angular momentum, with respect to the origin, at time t = 2 is :

The position of a particle is given by vec r = hat i + 2hat j - hat k and its momentum is vec p = 3 hat i + 4 hat j - 2 hat k . The angular momentum is perpendicular to

At a given instant of time the position vector of a particle moving in a circle with a velocity 3hat i - 4 hat j + 5 hat k is hat i + 9 hat j - 8 hat k . Its angular velocity at that time is: