A body sliding down on a smooth inclined plane slides down `1//4th` distane in 2s. I will slide down the complete plane in

A block sliding down on a rough 45^(@) inclined planes has half the velocity it would have been, the inclined plane is smooth. The coefficient of sliding friction between the the block and the inclined plane is

A block of mass m takes time t to slide down on a smooth inclined plane of angle of inclination theta and height h. If same block slids down on a rough inclined plane of same angle of inclination and same height and takes time n times of initial value, then coefficient friction between block and inclined plane is

Starting from rest , a body slides down at 45^(@) inclined plane in twice the time it takes to slide down the same distance in the absence of friction. The coefficient of friction between the body and the inclined plane is

Starting from rest a body slides down a 45^(@) inclined plane in twice the time it takes to slide down the same distance in the absence of friction. The coefficient of the body and the inclined plane is :

The time taken by a body to slide down a rough 45^(@) inclined plane is twice that required to slide down a smooth 45^(@) inclined plane. The coefficient of kinetic friction between the object and rough plane is given by

The time taken by a particle to slide down a smooth inclined plane is double the time it would take in falling down through a height equal to the vertical height of the plane. The inclination of the plane with horizontal is :

Starting from rest, the time taken by a body sliding down on a rough inclined plane at 45^(@) with the horizontal is twice the time taken to travel on a smooth plane of same inclination and same distance. Then, the coefficient of kinetic friction is

A block slides down a smooth inclined plane when released from the top, while another falls freely from the same point :