The mean kinetic energy of a gas at 300K is 100J .The mean energy of the gas at 450K" is equal to (A) 100J (B) 3000J (C) 450J (D) 150J

Internal energy of an ideal diatomic gas at 300 K is 100 J. In this 100 J

The mean kinetic energy of 1 kg-mol of nitrogen at 27^(@)C is 600 J . What will be its mean kinetic energy at 127^(@)C ?

The mean kinetic energy of 32 gm of oxygen at -73^(@)C is "........." in joule) (take R=8.3J/mole/k

Mean kinetic energy per gram mole of an ideal gas at 0^(@)C is nearly (R=8.320J//gm" mol"xxK)

The average kinetic energy of the molecules of a gas at 27^(@) is 9xx10^(-20)J . What is its average K.E. at 227^(@)C ?

Given, Avogadro's number N = 6.02 xx 10^23 and Boltzmann's constant k = 1.38 xx 10^-23 J//K . (a) Calculate the average kinetic energy of translation of the molecules of an ideal gas at 0^@ C and at 100^@ C . (b) Also calculate the corresponding energies per mole of the gas.

At two positons kinetic energy and potential energy of a particle are K_(1) =10J: U_(1) =-20J, K_(2) = 20 J, U_(2)=-10 J . In moving from 1 to 2 .