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Given bar(a)=bar(i)+2bar(j)+3bar(k),bar(...

Given `bar(a)=bar(i)+2bar(j)+3bar(k),bar(b)=2bar(i)+3bar(j)+bar(k),bar(c)=8bar(i)+13bar(j)+9bar(k)`, the linear relation among them if possible is

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bar(b)=bar(i)-2bar(j)-3bar(k),bar(b)=2bar(i)+bar(j)-bar(k),bar(c)=bar(i)+ 3bar(j)-2bar(k) then bar(a).(bar(b)xxbar(c))

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If three vectors bar(a)=bar(i)+bar(j)+bar(k),bar(b)=bar(i)-2a^(2)bar(j)+abar(k),bar(c)=bar(i)+(a+1)bar(j)-abar(k) are linearly dependent vectors then the real a lies in the interval.

The reciprocal of bar(a) where bar(a)=-bar(i)+bar(j)+bar(k),bar(b)=bar(i)-bar(j)+bar(k),bar(c)=bar(i)+bar(j)+bar(k) is

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If bar(a)=2bar(i)-bar(j)-bar(k),bar(b)=bar(i)+2bar(j)-3bar(k) and bar(c)=3mp mubar(j)+5bar(k) are coplanar then mu root of the equation