A projectile is thrown at an angle `theta` with the horizontal and its range is `R_(1)`. It is then thrown at an angle `theta` with vertical anf the range is `R_(2)`, then

A projectile is thrown at an angle of 40^@ with the horizontal and its range is R_1 Another projectile is thrown at an angle 40^@ with the vertical and its range is R_2 What is the relation between R_1 and R_2 ?

A projectile is thrown at an angle of 40^(@) with the horizontal and its range is R_(1) . Another projectile is thrown at an angle of 40^(@) with the vertical and its range is R_(2) . What is the relation between R_(1) and R_(2) ? (projection speed is same in both cases)

A ball is thrown at an angle theta with the horizontal and the range is maximum. The value of tantheta is:-

A stone is thrown with a velocity v at an angle theta with the horizontal.Its speed when it makes an angle beta with the horizontal is

A projectile is thrown at an angle of theta=45^(@) to the horizontal, reaches maximum reaches a maxium height of 16m , then

A stone projected from ground with certain speed at an angle theta with horizontal attains maximum height h_(1) when it is projected with same speed at an angle theta with vertical attains height h_(2) . The horizontal range of projectile is

Two projectiles A and B are thrown with the same speed such that A makes angle theta with the horizontal and B makes angle theta with the vertical, then -

When a projectile is fired at an angle theta w.r.t horizontal with velocity u, then its vertical component:

A projectile is projected with velocity u making angle theta with horizontal direction, find : horizontal range.