If the curve `y=f(x)` passing through the point `(1,2)` and satisfies the differential equation `xdy+(y+x^(3)y^(2))dx=0` ,then

If the curve y=f(x) passes through the point (1, -1) and satisfies the differential equation : y(1+xy)dx=x dy , then f(- 1/2) is equal to :

find the equation of the curve which passes through the point (2,2) and satisfies the differential equation y-x(dy)/(dx)=y^(2)+(dy)/(dx)

If a curve y=f(x) passes through the point (1,-1) and satisfies the differential equation ,y(1+xy)dx=xdy, then f(-(1)/(2)) is equal to: (A)-(2)/(5)(B)-(4)/(5)(C)(2)/(5)(D)(4)/(5)

If y=f(x) passing through (1,2) satisfies are differential equation y(1+xy)dx-x dy=0, then

The equation of the curve passing through the point (1,1) and satisfying the differential equation (dy)/(dx) = (x+2y-3)/(y-2x+1) is

Show that the equation of the curve passing through the point (1,0) and satisfying the differential equation (1+y^2)dx-xydy=0 is x^2-y^2=1

Show that the equation of the curve passing through the point (1,0) and satisfying the differential equation (1+y^2)dx-xydy=0 is x^2-y^2=1

The graph of the function y = f(x) passing through the point (0, 1) and satisfying the differential equation (dy)/(dx) + y cos x = cos x is such that

A curve passes through (1,0) and satisfies the differential equation (2x cos y+3x^(2)y)dx+(x^(3)-x^(2)sin y-y)dy=0