When `(0,0)` shifted to `(3,-3)` the co-ordinates of `P, Q, R` are `(5,5),(-2,4) and (7,-7)` in the new system are `A, B, C` then area of triangle `ABC` in sq units is

In Fig.3, the area of triangle ABC( in sq.units ) is :

When (0,0) is shifted to (sqrt(7),2+sqrt(3)) the coordinates of P(5,5), Q(-2,4) and R(7,-7) in the new system are A, B, C . Then area of /_\ABC is:

When (0,0) is shifted to (3,-3) then the points P(5,5),Q(-2,4) and R(7,-7) are changed as A,B,C and if the area of triangle ABC is k then (86)/(k) is

If the co-ordinate of the triangle P(4,5),Q(8,2) and origin then find the Area of triangle ?

If the co - ordinate of the triangle P(4,3) Q (7,-1) and R (9,3) is then find the Area of triangle PQR and also find the types of triangle ?

Point R divides line joining A(-5, 1) and B(3, 5) in the ratio lambda:1 . The co - ordinates of P and Q are (1, 5) and (7, 2) respectively. If the area of the triangle PQR be 2 sq. units, then the value of lambda is

Let A(1, 1, 1), B(3, 7, 4) and C (-1, 3, 0) be three points in a plane. Area of the triangle ABC is (in sq. units)

In a triangle ABC, coordinate of A are (1,2) and the equations of the medians through B and C are respectively, x+y=5&x=4 . Then area of DeltaABC (in sq. units) is:

The coordinates of the point (4,5) in the new system,when its origin is shifted to (3,7) are

The coordinates of the point (4,5) in the new system,when its origin is shifted to (3,7) are