A stone is projected from a horizontal plane. It attains maximum height `H` & strikes a stationary smooth wall & falls on the ground vertically below the maximum height. Assuming the collision to be elastic the height of the point on the wall where ball will strike is

A stone is projected vertically from the ground.It reaches the maximum height of 500m in 10 sec.After what time it will reach the ground from the maximum height reached?

A stone is projected vertically up to reach maximum height h. The ratio of its potential energy to its kinetic energy at a height 4/5h , will be

A stone projected at angle 53^(@) attains maximum height 25m during its motion in air. Then its distance from the point of projection where it will fall is

Maximum height attained from the point of projection is:

A stone is projected vertically upward to reach maximum height h. The ratio of its kinetic energy to its potential energy at a height (4)/(5) h, will be

A ball is projected to attain the maximum range. If the height attained is H, the range is

For an object projected from ground with speed u horizontal range is two times the maximum height attained by it. The horizontal range of object is

If the horizontal range of a projectile be a and the maximum height attained by it is b, then prove that the velocity of projection is

A ball is projected from a point in a horizontal plane so as to strike a vertical wall at right angle A .after rebounding from the wall it strikes the horizontal plane once and returns to the point of projection just before second collision at horizontal surface. Find co-efficient of restitution for the two collisions, assuming it to be same for both the collision.