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A particle is projected at time t=0 from...

A particle is projected at time t=0 from a point (P) with a speed `v_(0)` at an angle of `45^(@)` to the horizontal.The magnitude of angular momentum of the particle about the point (P) at time `(t=(v_(0))/(g))` is `(mv_(0)^(3))/(2g sqrt(X))` .Then the value of X is?

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