[" For a closed surface "],[" the flux associated is "phi],[" .On adding "75 mu C" to it,"],[" it becomes "4^(phi)." Find "],[" out initial charge "],[" enclosed by surface "]

When a 10 muC charge is enclosed by a closed surface, the flux passing through the surface is phi . Now another 10 µC charge is placed inside the closed surface, then the flux passing through the surface is ______.

20 mu C charge is placed inside a closed surface then flux related to surface is phi . If 80 mu C charge is added inside the surface then charge in flux is :-

Assertion : If a dipole is enclosed by a surface, then according to Gauss's law, electric flux linked with it will be zero. Reason : The charge enclosed by a surface is zero.

Find out flux through given gaussian surface.

Find out flux through the given Gaussian surface.

The total electric flux phi through the entire area of a closed surface is given by

5x10^(5) lines of electric flux are entering in a closed surface and 4x10^(5) liner come out of the surface the charge enclosed by the surface is-

Flux (in S.I. units) coming out and eantering a closed surface is shown in the figure. Find change enclosed by the closed surface.

A : If electric flux over a closed surface is negative then the surface encloses net negative charge. R : Electric flux is independent of the charge distribution inside the surface.