`int_0^(pi/2) sin^6x dx`

int_0^(pi/2) sin x dx

Evaluate int_0^(pi/2) sin^7x dx

(i) int_0^(pi/2) sin^2 x dx (ii) int_0^(pi//2) cos^2 x dx

IF int_0^a sqrtx dx=2a int_0^(pi//2) sin^3 x dx, find int_a^(a+1) x dx .

int_0^(pi//2) sin^3 x dx

Sketch the regions represented by the following: (i) int_0^1 x^2 dx (ii) int_0^(pi/2) sin x dx

The value of the integral int_(0)^(pi//2) sin^(6) x dx , is

int_(0)^(pi//2)sin^(6)x cos^(2)x dx=

The value of int_(0)^(2) 3x^(2)dx+int_(0)^(pi//2) sin x dx is :-

Compute the integrals : (a) int_(0)^(pi//2) sin 2x dx , (b) int_(pi//6)^(pi//2) (cos x)/(sin^(3) x) dx (c) int_(0)^(1) (dx)/( sqrt(16 - x^(2)))