`A=[[0,1],[3,0]]" and let "BV=[[0],[11]]" Where "B=A^(8)+A^6+A^(4)+A^(2)+I," (Where "I" is the "2times2" identity matrix) then the product of all elements of matrix "V" is "`

A=[[0,13,0]] and A^(8)+A^(6)+A^(2)+IV=[[011]] (where Iis the 2xx2 identity matrix ), then the product of all elements of matrix V is

If A = [[0, 1],[3,0]]and (A^(8) + A^(6) + A^(4) + A^(2) + I) V= [[0],[11]], where V is a vertical vector and I is the 2xx2 identity matrix and if lambda is sum of all elements of vertical vector V , the value of 11 lambda is

If A=[[1,0,-32,1,30,1,1]], then verify that A^(2)+A=A(A+I), where I is the identity matrix.

Let A=[(2,0,7),(0,1,0),(1,-2,1)] and B=[(-k,14k,7k),(0,1,0),(k,-4k,-2k)] . If AB=I , where I is an identity matrix of order 3, then the sum of all elements of matrix B is equal to

Let B=A^(3)-2A^(2)+3A-I where l is an identity matrix and A=[(1,3,2),(2,0,3),(1,-1,1)] then the transpose of matrix B is equal to

Let A=[[0,10,0]] show that (aI+bA)^(n)=a^(n)I+na^(n-1)bA where I is the identity matrix of order 2 and n in N

A square matrix P satisfies P^(2)=I-p where I is the identity matrix and p^(x)=5I-8p, then x

If A=[[1,4,0],[5,2,6],[1,7,1]] and A^(-1)=(1)/(36)(alpha A^(2)+beta A+yI), where I is an identity matrix of order 3, then value of alpha, beta, gamma