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If A=tan^(-1)(1/7)" and B=tan^(-1)(1/3) ...

If A=`tan^(-1)(1/7)" and B=tan^(-1)(1/3)` then tan(A+B)

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If A=tan^(-1)(1/7) and B=tan^(-1)(1/3) then A+B=

If A=tan^(-1)(1//7), B=tan^(-1)(1//3) , then

tan^(-1)7-tan^(-1)5=tan^(-1)(1/18)

If tan A=(1)/(2) and tan B=(1)/(3), then tan(2A+B) is

tan^(-1)3-tan^(-1)2=tan^(-1)(1/7)

tan^(-1)3-tan^(-1)2=tan^(-1)(1/7)

If A=tan1 and B=tan^(-1)1 then

If A = tan 1 and B =tan ^(-1) 1 then

tan^(-1) (1/5) + tan^(-1) (1/7) + tan^(-1) (1/3) + tan^(-1) (1/8) = π/4

tan^(-1)7-tan^(-1)5=tan^(-1)(1)/(18)