If AD, BE and CF are the medians of a `Delta ABC,` then evaluate `(AD^(2)+BE^(2)+CF^(2)): (BC^(2) +CA^(2) +AB^(2)).`

If AD, BE and CF are the medians of a ABC ,then (AD^(2)+BE^(2)+CF^(2)):(BC^(2)+CA^(2)+AB^(2)) is equal to

If AD , BE and CF are medians of DeltaABC , then bar(AD) + bar(BE) + bar(CF) =

AD BE and CF are the medians of a Delta ABC .Prove that 2(AD+BE+CF)<3(AB+BC+CA)<4(AD+BE+CF)

If AD, BE and CF be the median of a /_\ABC , prove that vec(AD)+vec(BE)+vec(CF) =0

ABC is a given triangle. AD, BE and CF are altitudes of DeltaABC . Assertion (A) : (AB^(2)+BC^(2)+CA^(2)) gt (AD^(2)+BE^(2)+CF^(2)) Reason (R) : (AE^(2)-AF^(2))+(BF^(2)-BD^(2))+(CD^(2)-CE^(2))=0

If AD is the median of Delta ABC, using vectors,prove that AB^(2)+AC^(2)=2(AD^(2)+CD^(2))

If the AD,BE,CF are the lengths of the medians of a DeltaABC then general solution of the equation cos theta=sqrt((AD^(2)+BE^(2)+CF^(2))/(AB^(2)+BC^(2)+CA^(2))) is (where z is the set of all integers)

If O is the centroid and AD, BE and CF are the three medians of Delta ABC with an area of 96 cm^(2) then the area of Delta BOD in cm^(2) is

In a Delta ABC,AD,BE and CF are three medians. The perimeter of Delta ABC is always.

If AD, BE and CF are medians of triangle ABC then prove that median AD divides line segment EF.