Let a funtion `f` defined on te set of all integers satisfy `f(0)ne,f(1)=3` and
`f(x).f(y)=f(x+y)+f(x-y)` for all integers x and y. then

Let f be a funcation defined on the set of all positive integers such that f (x) +f(y) for all postive integers x,y,if f (12) =24 and f(8) =15 the value of f(48) is

Let be a real function satisfying f(x)+f(y)=f((x+y)/(1-xy)) for all x ,y in R and xy ne1 . Then f(x) is

Let f:R to R such that f(x+y)+f(x-y)=2f(x)f(y) for all x,y in R . Then,

f(x) is a real valued function, satisfying f(x+y)+f(x-y)=2f(x).f(y) for all yinR , Then

If f(x) a polynomial function satisfying f(x)f(y)=f(x)+f(y)+f(xy)-2 for all real x and y and f(3)=10 ,then f(4)-8 is equal

If f(x-y), f(x) f(y) and f(x+y) are in A.P. for all x, y in R and f(0)=0. Then,

Let f(x) and g(x) be functions which take integers as arguments.Let f(x+y)=f(x)+g(y)+8 for all intege x and y.Let f(x)=x for all negative integers x and let g(8)=17. Find f(0) .