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A body is sliding down an inclined plan...

A body is sliding down an inclined plane having coefficient of friction 0.5 .If the normal reaction is 4 times that of the resultant downward force along the incline, find the angle between the inclined plane and the horizontal.

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A body is sliding down an inclined plane having coefficient of friction 1/3. If the normal reaction is three times that of the resultant downward force along the incline, the angle between the inclined plane and the horizontal is ?

A body is sliding down an inclined plane having coefficient of friction 0.5. If the normal reaction is twice that of resultant downward force along the inclined plane, then find the angle between the inclined plane and the horizontal .

Knowledge Check

  • A body is sliding down an inclined plane having coefficient of friction 1//3 . If the normal reaction is three times that of the resultant downward force along the inclined plane, the angle between the inclined plane and the horizontal is

    A
    `tan^(-1)[(1)/(2)]`
    B
    `tan^(-1)(2)`
    C
    `tan^(-1)((2)/(3))`
    D
    `tan^(-1)((3)/(2))`

  • A body is sliding down an inclined plane (mu = (1)/(2)) . If the normal reaction is twice that of the resultant downward force along the incline , the inclination of plane is

    A
    `15^(@)`
    B
    `30^(@)`
    C
    `45^(@)`
    D
    `60^(@)`

  • When a body slides down an inclined plane with coefficient of friction as mu_(k) then its acceleration is given by

    A
    `g(mu_(k)sin theta+cos theta)`
    B
    `g(mu_(k)sin theta-cos theta)`
    C
    `g(sin theta+mu_(k) costheta)`
    D
    `g(sin theta-mu_(k)cos theta)`

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