The energy released by complete fission of one kilogram of `""^(235)U` is equal to that released by complete burning of

The enegry released per fission of .^(235)u is nearly

The energy released by fission of one U^(235) atom is 200 MeV. Calculate the energy released in kWh, when one gram of uranium undergoes fission.

Calculate the energy released by the fission 1 g of .^(235)U in joule, given that the energy released per fission is 200 MeV . (Avogadro's number =6.023xx10^(23))

The energy released during the fission of 1kg of U^(235) is a E_1 and that product during the fusion of 1 kg of hydrogen is E_2 . If energy released per fission of Uranium - 235 is 200 MeV and that per fusion of hydrogen is 24.7 MeV , then the ratio E_2/E_1 is

Most of energy released in the fission is carried by

(a) Calculate the energy released by the fission of 2g of ._(92)U^(235) in kWh . Given that the energy released per fission is 200MeV . (b) Assuming that 200MeV of enrgy is released per fission of uranium atom, find the number of fissions per second required to released 1 kilowatt power. (c) Find the amount of energy produced in joules due to fission of 1g of ._(92)U^(235) assuming that 0.1% of mass is transformed into enrgy. ._(92)U^(235) = 235 amu , Avogadro number = 6.023 xx 10^(23)

Calculate the energy released by fission of 1 g of ._(92)^(235)U , assuming that an energy of 200 MeV is released by fission of each atom of .^(235)U . (Avogardo constant is = 6.023 xx 10^(26) kg mol^(-1) )

The energy liberated on complete fission of 1 kg of ._92 U^235 is (Assume 200 MeV energy is liberated on fission of 1 nucleus).