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If bar(P(1)P(2)) is perpendicular to bar...

If `bar(P_(1)P_(2))` is perpendicular to `bar(P_(2)P_(3))` ,then the value of `k` is where `P_(1)(k,1,-1),P_(2)(2k,0,2)` &, `P_(3)(2+2k,k,1)`

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