If `y=2` is directrix and `(0,1)` be the vertex of parabola `x^(2)+lamday+mu=0` then, `(lamda-mu)=`?

If y=2 is the directrix and (0,1) is the vertex of the parabola x^2+lambday+mu=0 , then (a)lambda=4 (b) mu=8 (c) lambda=-8 (d) mu=4

The vertex of the parabola y^(2)+6x-2y+13=0 is

Vertex of the parabola x ^(2) +4x + 2y -7=0 is

Vertex of the parabola y ^(2) + 2y + x=0 lies in the

The directrix of the parabola y^(2)+4x+3=0 is

Find the vertex and the directrix of the parabola y^2 - 3x-2y+7=0

Find vertex, focus, directrix and latus rectum of the parabola y^(2)+4x+4y-3=0 .

If (2,0) is the vertex and y-axis the directrix of a parabola then its focus is

If (2,0) is the vertex and y-axis the directrix of a parabola then its focus is