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(x+y)(dx-dy)=dx+dy, where x+y=u...

`(x+y)(dx-dy)=dx+dy`, where `x+y=u`

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1+(dy)/(dx)=cos(x+y), where x+y=u

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Solve (x-y)(dx+dy)=dx-dy , given that y=-1 , where x=0 .

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