A charged oil drop falls with terminal velocity `v_(0)` in the absence of electric field. An electric field E keeps it stationary. The drop acquires charge 3q, it starts moving upwards with velocity `v_(0)`. The initial charge on the drop is

A charged oil drop falls terminal velocity V_0 in the absence of electric field . An electric field E keeps it stationary . The drop acquires additional charge q and starts moving upwards with velocity V_(0) . The intial charge on the drop was .

A charged oil drop fall with a terminal velocity V in the absence of elcectric field . An electric field E keep keep the oil drop stationary in it . When the drop acquire a charge 'q' it moves up with same velocity. Find the initial charge on the drop.

A charge oil drop of charge q is falling under gravity with termined velocity v in the absence of electric filed . A electric field can keep the oil drop stationary . If the drop acquires an additional charge , it moves up with velocity 3v in that field . find the new charge on the drop.

In Milikan's oil drop experiment, a charged drop falls with terminal velocity V. If an electric field E is applied in vertically upward direction then it starts moving in upward direction with terminal velocity 2V. If magnitude of electric field is decreased to (E)/(2) , then terminal velocity will become

In Milikan's oil drop experiment, a charged drop falls with terminal velocity V. If an electric field E is applied in vertically upward direction then it starts moving in upward direction with terminal velocity 2V. If magnitude of electric field is decreased to (E)/(2) , then terminal velocity will become

An oil drop having a charge q and apparent weight W falls with a terminal speed v in absence of electric field . When electric field is switched on it starts moving up with terminal speed v. The strength of electric field is

An oil drop having a charge q and apparent weight W falls with a terminal speed v in absence of electric field . When electric field is switched on it starts moving up with terminal speed v. The strength of electric field is

An oil drop of mass m fall through air with a terminal velocity in the presence of upward electric field of intensity E . the drop carries a charge +q . R is the viscous drag force and f is the buoyancy force . Them for the motion of the drop.

An electric charge q is moving with a velocity w in the direction of a magnetic field B. The magnetic force acting on the charge is