The two chords AB and AC of a circle are equal. Prove that the bisector of `angle BAC` passes through the centre.

The two chords AB and AC of a circle are equal, prove that the bisector, of angleBAC passes through the centre of the circle.

Two chords AB and AC of a circle are equal. Prove that the centre of the circle lies on the angle bisector of /_BAC.

Two chord AB and AC of a circle are equal. Prove that the centre of a circle lies on the angle bisector of /_BAC

Two chords AB and AC of a circle are equal. Prove that the centre of the circle lies on the angle bisector of angleBAC .

Two chords A B and A C of a circle are equal. Prove that the centre of the circle lies on the angle bisector of /_B A Cdot

Two chords A B and A C of a circle are equal. Prove that the centre of the circle lies on the angle bisector of /_B A Cdot

If two chords AB and AC of a circle with centre O are such that the centre O lies on the bisector of /_BAC, prove that AB=AC, i.e. the chords are equal.

If two equal chords intersect each other, then the bisector of the angle between them pass through the centre.

Length of two chords AB and AC of a circle are respectively 8 cm and 6 cm and angle BAC = 90^@ . What is the radius of the circle?

If two chords AB and AB of a circle with centre O are such that the centre O lies on the bisector of /_BAC; Prove that AB=AC