A man walks for `1 "minute" ` at a speed of `1 m s^(-1)` and then runs for `1 min` at a speed of `3 ms ^(-1)` along straight track, What is the average speed of the man?

A man walks for 1 minute at a speed of 1m/s and then runs for 2 minute at 3m/s. What is the average speed of the man?

A man walks for 1 minute at a speed of 1m/s and then runs for 2 minute at 3m/s. What is the average speed of the man?

Compute your average velocity in the following two cases, (a) You walk 73.2 m at a speed of 1.22 m/s and then run 73.2 m at a speed of 2.85m/s along a straight track. (b) you walk for 1.00 min at a speed of 1.22 m/s and then run for 1.00 min at 3.05 m/s along a straight track. (c) Graph x versus t for both cases and indicate how the average velocity is found on the graph.

A body moves at a speed of 100 ms^(-1) for 10 s and then moves at a speed of 200 m s^(-1) for 20 s along the same direction. The average speed is …………………………….,

A body moves at a speed of 100 ms^(-1) for 10 s and then moves at a speed of 200 m s^(-1) for 20 s along the same direction. The average speed is …………………………….,

A man walks on a straight road from his home to a market 2.5 km away with a speed of 5 km. h^(-1) . Finding the market closed he instantly turns and walks back home with a speed of 7.5 km. h^(-1) . What is the average speed of the man over the interval of time (i) 0 to 30 min (ii) 0 to 50 min (iii) 0 to 40 min? [Note: you will appreciate speed as total path length divided by time and not as magnitude of average velocity. You would not like to tell the tired man on his return home that his average speed was zero! ]

At 27^(@)C a gas contains 10 molecules travelling with a speed of 4 ms^(-1) , 20 molecules travelling with a speed of 5 m s^(-1) and 40 molecules travelling with a speed of 8 m s^(-1) . Calculate the average speed, root mean square speed and most probable speed of the gas at 27^(@)C .

A man runs towards a mirror with a speed of 15 m-s^(-1) . What is the speed of his image?

A man walks at a speed of 6 km h^-1 for 1 km and 8 km h^-1 for the next 1 km.What is the average speed for the walk fo 2 km?

A man walks on a straight road from his home to a market 2.5 km away with a speed of 5 km h ^-1 . Finding the market closed, he instantly turns and walks back home with a speed of 7.5 km h^-1 . What is the average speed of the man over the interval of time (i) 0 to 30 min, (ii) 0 to 50 min, (Hi) 0 to 40. min? [Note: You will appreciate from this exercise why . it is better to define average speed as total path length divided by time, and not as magnitude of average velocity. You would not like to tell the tired man on his return home that his average speed was zero!]